SOLUTION: Log{subscript 8}x + log{subscript 8}(x-2)=2

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Question 631802: Log{subscript 8}x + log{subscript 8}(x-2)=2
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Log{subscript 8}x + log{subscript 8}(x-2)=2
log8(x)+log8(x-2)=2
log8[x(x-2)]=2
exponential form:
8^2=x(x-2)
x^2-2x=64
x^2-2x-64=0
use following quadratic formula to solve:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a=1, b=-2, c=-64
ans:
x=-7.062 (reject, x>0)
or
x=9.062