SOLUTION: how do you find three consecutive odd positive integers such that 2 times the sum of all three is 9 less than the product of the first and second integers

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Question 631790: how do you find three consecutive odd positive integers such that 2 times the sum of all three is 9 less than the product of the first and second integers
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

three consecutive odd positive integers highlight%28x%29, highlight%28x+%2B+2%29 , highlight%28x%2B4%29

2 times the sum of all three is 9 less than the product of the first and second integers

  2(3x + 6)=x(x+2)-9

    6x + 12  = x^2 + 2x-9

           0 = x^2-4x - 21

           0 =  (x-7)(x+3)    x = 7 

The  three consecutive odd positive integers are 7 , 9 , 11



and...

  2%2A27+=+54+=+7%2A9++-+9