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| Question 631734:  Please help me solve this problem:
 The length of a rectangle is 7 cm more than its width. If the length is increased by 2 cm and the width increased by 4 cm, the area will be increased by 54 cm^2. Find the original length and width of the rectangle.
 Thank you so much!
 Answer by MathTherapy(10556)
      (Show Source): 
You can put this solution on YOUR website! Please help me solve this problem:
 The length of a rectangle is 7 cm more than its width. If the length is increased by 2 cm and the width increased by 4 cm, the area will be increased by 54 cm^2. Find the original length and width of the rectangle.
 Thank you so much!
 
 Let original width of rectangle be W
 Then original length = W + 7
 Increasing length by 2 makes it W + 7 + 2, or (W + 9) cm
 Increasing width by 4 makes it (W + 4) cm
 
 Original area = LW, or W(W + 7), or
  Adjusted area = LW, or (W + 9)(W + 4), or
   
 Since adjusted area is increased by
  , then: 
   
   
 13W - 7W = 20
 6W = 20
 
 W, or original width =
  , or  , or  cm 
 Original length = W + 7, or
  , or  , or  cm 
 You should be able to do the check!!
 
 Send comments and “thank-yous” to “D” at  MathMadEzy@aol.com
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