SOLUTION: completely factor the expression 48u^4v^4-18u^2v^2-3u^8v^5 a. nonfactorable b. 3u^2v^2(16u^2v^2-6-u^6v^3) c. 3(16u^4v^4-6u^2v^2-u^8v^5) d. u^2v^2(48u^2v^2-18-3u^6v^3) I am l

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: completely factor the expression 48u^4v^4-18u^2v^2-3u^8v^5 a. nonfactorable b. 3u^2v^2(16u^2v^2-6-u^6v^3) c. 3(16u^4v^4-6u^2v^2-u^8v^5) d. u^2v^2(48u^2v^2-18-3u^6v^3) I am l      Log On


   



Question 631729: completely factor the expression 48u^4v^4-18u^2v^2-3u^8v^5
a. nonfactorable
b. 3u^2v^2(16u^2v^2-6-u^6v^3)
c. 3(16u^4v^4-6u^2v^2-u^8v^5)
d. u^2v^2(48u^2v^2-18-3u^6v^3)
I am lost on this one for some reason I cant figure it out

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
completely factor the expression (by Using the Greatest Common Factor)
48u%5E4v%5E4-18u%5E2v%5E2-3u%5E8v%5E5+
IF you were to explore b.+3u%5E2v%5E2%2816u%5E2v%5E2-6-u%5E6v%5E3%29which says... ALL terms have 3u%5E2v%5E2 in common
||x%5Em%2Fx%5En=x%5E%28m-n%29
You would find 'b' to be the correct answer to factoring completely.
It is a GRReat advantage to have a multiple choice format.
Recommend using that advantage as a guide you to a correct selection.