SOLUTION: how do i rearragne and sketch a graph witht the following equations 4x-y=5 & 3x-2y=8 with the steps please thanks!

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Question 631692: how do i rearragne and sketch a graph witht the following equations
4x-y=5
&
3x-2y=8
with the steps please thanks!

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Those equations are linear equations.
Their graphs are straight lines.
To graph a straight line you only need to locate 2 points.
Sometimes you do not even need to rearrange the equation to figure out 2 points for the line.
In this case, I would rearrange.
4x-y=5 --> 4x-y%2By-5=5%2By-5 (adding y-5 to both sides of the equal sign)
4x-y%2By-5=5%2By-5 --> 4x-5=y or y=4x-5
Now we need 2 points from that line.
x=0 makes calculations easy and give us y=-5 for point (0,-5)
x=2 results in y=4%2A2-5 --> y=8-5 --> y=3 for point (2,3)
We can plot the points and then connect them with a line:

Similarly, for the other line,
3x-2y=8 --> 3x-2y%2B2y-8=8%2B2y-8 --> 3x-8=2y or 2y=3x-8
Now we divide both sides by 2
2y=3x-8 --> 2y%2F2=%283x-8%29%2F2 --> y=3x%2F2-8%2F2 --> y=%283%2F2%29x-4
For the point, we can use
x=0 --> y=-4 for point (0,-4) , and
x=2 --> y=%283%2F2%29%2A2-4 --> y=3-4 --> y=-1 for point (2,-1)
Then we add to the graph the new points and connect them with a second line:

Sometimes from the graph you can solve the system of equations.
In this case, the solutions have fractions, and you cannot guess them from the graph.
You need to solve the system algebraically, finding x=2%2F5=0.4, y=-17%2F5=-3.4 , to find out that the lines intersect at (2%2F5, -17%2F5) .