Question 63167: find an equation of the circle centered at (6,-5) and passing through (1,7)
thank you
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find an equation of the circle centered at (6,-5) and passing through (1,7)
thank you
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If it passes thru (1,7) the length of the radius is:
r=sqrt[(7--5)^2+(1-6)^2]=sqrt[144+25]=sqrt169=13
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With the center at (6.-5) and radius = 13 the equation is:
(x-6)^2 + (y+5)^2=13^2
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Cheers,
Stan H.
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