SOLUTION: Find all real numbers in the interval [0,2pi] that satisfy the equation. Round to the nearest hundredth.
cos x = -0.23
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-> SOLUTION: Find all real numbers in the interval [0,2pi] that satisfy the equation. Round to the nearest hundredth.
cos x = -0.23
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Question 631631: Find all real numbers in the interval [0,2pi] that satisfy the equation. Round to the nearest hundredth.
cos x = -0.23 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find all real numbers in the interval [0,2pi] that satisfy the equation. Round to the nearest hundredth.
cos x = -0.23
arccos(-0.23)=1.803( in quadrant II where cos<0)
reference angle=π-1.803=1.339
2nd angle=1.339+π=4.481 (in quadrant III where cos is also<0)
all real numbers in the interval [0,2pi]: 1.803 and 4.481 radians
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