SOLUTION: completely factor the expression 2a^3-128 a. 2(a-4)(a^2+4a+16) b. 2(a^3-64) c. prime d. 2(a-4)^3 If you could please explain I would really appreciate it

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: completely factor the expression 2a^3-128 a. 2(a-4)(a^2+4a+16) b. 2(a^3-64) c. prime d. 2(a-4)^3 If you could please explain I would really appreciate it      Log On


   

Question 631475: completely factor the expression 2a^3-128
a. 2(a-4)(a^2+4a+16)
b. 2(a^3-64)
c. prime
d. 2(a-4)^3
If you could please explain I would really appreciate it
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
2a%5E3-128 Start with the given expression


2%28a%5E3-64%29 Factor out the GCF 2


2%28a%5E3-4%5E3%29 Rewrite 64 as 4%5E3


2%28a-4%29%28a%5E2%2B4a%2B16%29 Now use the difference of cubes rule to factor


So 2a%5E3-128 completely factors to 2%28a-4%29%28a%5E2%2B4a%2B16%29

Which means that the answer is choice A

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