Question 63144: I need serious help
8(5-y)=64
-3x=-5(x-8)
4(m-4)=3(m+5)
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Just follow the simple rules of algebra to isolate the variable on the left
Here it is step-by-step
:
8(5-y) = 64
normally you would mult what's inside brackets, however, here we can simplify
things by dividing both sides by 8; this would give us:
1(5-y) = 8
5 - y = 8
subtract 5 from both sides:
5 -5 -y = 8 - 5
-y = +3
Our variable (y), has to be positive, so mult eq by -1, gives us:
y = - 3
:
check our solution in the original equation:
8(5-y) = 64
8(5 - (-3)) = 64
8(5 + 3) = 64; remember, a minus a minus, is a plus
8(8) = 64
:
:
-3x=-5(x-8)
Mult what's inside the brackets:
-3x - 5x + 40
Add 5x to both sides:
5x - 3x = -5x + 5x + 40
2x = 40
Divide both sides by 2
1x = 40/2
x = + 20
:
Check our solution: -3(20) = -5(20-8)
:
:
4(m-4) = 3(m+5)
Mult what's inside the brackets:
4m - 16 = 3m + 15
Subtract 3m from both sides and you have:
4m - 3m - 16 = -3m + 3m + 15
1m - 16 = 15
Add 16 to both sides:
m - 16 +16 = 15 + 16
m = 31
:
Check our solution:
4(31 - 4) = 3(31 + 5)
4(27) = 3(36)
:
It's a good idea to prove that your solution is correct like we did here.
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