SOLUTION: How do you write the binomial expansion for question # 1 & 2? 1. (2x+3)3 < - -3rd power 2. (2x-y)6 < - - 6th power 3. What is the 3rd term of the expansion for (x+3)7 < -

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Question 631210: How do you write the binomial expansion for question # 1 & 2?
1. (2x+3)3 < - -3rd power
2. (2x-y)6 < - - 6th power
3. What is the 3rd term of the expansion for (x+3)7 < - - 7th power
4. What is the 5th term of the expansion for (2x-3y)5 < - - 5h power
5. find the coefficient of x3 < - - x to the 3rd power in the expansion (x+3)5 < - 5th power
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
write the binomial expansion for question # 1 & 2?
1. (2x+3)^3 = 3C3*(2x)^3 + 3C2*(2x)^2*3 + 3C1(2x)*3^2 + 3C0*3^3
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2. (2x-y)^6
Same pattern as above but starting with 6C6
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3. What is the 3rd term of the expansion for (x+3)^7
Ans: 7C5(x^5)(3^2)
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4. What is the 5th term of the expansion for (2x-3y)^5
Ans: 5C1(2x)(-3y)^4
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5. find the coefficient of x3 in the expansion (x+3)^5
Ans: 5C3(x^3)*3^2
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Cheers,
Stan H.

SOLUTION: How do you write the binomial expansion for question # 1 & 2? 1. (2x+3)3 < - -3rd power 2. (2x-y)6 < - - 6th power 3. What is the 3rd term of the expansion for (x+3)7 < - - 7t