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Question 63117: How do you solve for x: 3/2x+4x-3(2/3x+1/3-2)=2(5-1/2+3/2)also how do you solve for x: 2x+6x-4(3/2x+5)=4x-1/2+6x-5/2 please help me!?! Idont understand what and how to start the equation and how to get the answer.
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! (3/2)X+4X-3([2/3]X+1/3-2)=2(5-1/2+3/2)
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(3/2=1.5),(-3*2/3=-6/3=-2),(-3*1/3=-1),(-3*-2=6),(5-[1/5=.5].5+[3/2=1.5]1.5=6)
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HOPE THIS HELPS.
WHAT GRADE ARE YOU IN? DOESN'T THE TEACHER EXPLAIN HOW TO HANDLE ITEMS WITH () AND THE SEQUENCE OF OPERATIONS (POWERS, MULTIPLY/DIVIDE THEN ADD/SUBTRACT, LEFT TO RIGHT)??????????
IF YOU AREN'T TAUGHT THE VERY BASICS YOU'LL NEVER BE ABLE TO LEARN HOW TO DO ALGEBRA.
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1.5X+4X-2X-1+6=2(6)
3.5X+5=12
3.5X=7
X=7/3.5
X=2 PROOF
PROOF
1.5*2+4*2-3([2/3]2+1/3-2)=12
3+8-3*2-2*2+3*1/3-2*-3=12
3+8-4-1+6=12
11-5+6=12
12=12
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