SOLUTION: X^2*x^4*x (-7x)^3 (2b^3)^4 a^8/a^11 NEED HELP ASAP PLEASE-DIRECTIONS SAY SIMPLIFY for these 4 problems! Thanks in advance!

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Question 631070: X^2*x^4*x
(-7x)^3
(2b^3)^4
a^8/a^11
NEED HELP ASAP PLEASE-DIRECTIONS SAY SIMPLIFY for these 4 problems! Thanks in advance!
Found 2 solutions by stanbon, 55305:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
X^2*x^4*x = X^(2+4+1) = X^7
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(-7x)^3 = -343x^3
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(2b^3)^4 = 16b^12
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a^8/a^11 = 1/a^3
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Cheers,
Stan H.
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Answer by 55305(86) (Show Source):
You can put this solution on YOUR website!
1.We just need to add the powers up. 2+4+1=7 answer: x^7
2.We just find -7^3 and x^3 and multiply them together. -7^3=-343, x^3=x^3, so the answer is -343x^3.
3.We just need to find 2^4*(b^3)^4=16*b^(3*4)=16b^12.
4.We just need to subtract 11 from 8. 8-11=-3, answer:a^-3, which is the same as 1/a^3.