SOLUTION: What is the standard form equation of the line passing through (3, –2) with a slope of 3/5

Algebra ->  Linear-equations -> SOLUTION: What is the standard form equation of the line passing through (3, –2) with a slope of 3/5      Log On


   

Question 630978: What is the standard form equation of the line passing through (3, –2) with a slope of 3/5
Found 2 solutions by lwsshak3, lenny460:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What is the standard form equation of the line passing through (3, –2) with a slope of 3/5
Standard form of equation for a straight line: y=mx+b, m=slope, b=y-intecept
equation: y=3x/5+b
solve for b using given point (3, -2)
-2=3*3/5+b
b=-2-9/5=-10/5-9/5=-19/5
equation: y=3x/5-19/5

Answer by lenny460(1073) About Me  (Show Source):
You can put this solution on YOUR website!
What is the standard form equation of the line passing through (3, –2) with a slope of 3/5

We use the formula:

y - y1 = m(x - x1)
y - (-2) = 3/5(x - 3)
y - (-2) = y + 2
Now we have:
y + 2 = 3/5(x - 3)
Cross multiply:
5(y + 2) = 3(x - 3)
5 * y = 5y
5 * 2 = 10
3 * x = 3x
3 * -3 = -9
Therefore:
5y + 10 = 3x - 9
Subtract 10 from each side of the equation.
5y + 10 - 10 = 3x - 9 - 10
Combine like terms:
10 - 10 = 0
-9 - 19 = -19
Therefore:
5y = 3x - 19
Divide each item by 5
5y/5 = 3x/5 - 19/5
y = 3x/5 - 19/5

The Answer:
y = 3x/5 - 19/5



Lennox Obuong
Algebra Student
Email: obuong3@aol.com