SOLUTION: Solve the equation for exact solutions over the interval [0,2pi) Sec^2 x - 2 = tan^2 x
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Question 630554
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Solve the equation for exact solutions over the interval [0,2pi)
Sec^2 x - 2 = tan^2 x
Answer by
lwsshak3(11628)
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Solve the equation for exact solutions over the interval [0,2pi)
Sec^2 x - 2 = tan^2 x
**
identity: tan^2x=sec^2x-1
sec^2x-2=sec^2x-1
-2≠-1
no solution. problem may have been written in error