SOLUTION: At the park there is a pool shaped like a circle with radius 11yd. A ring-shaped path goes around the pool. Its width is 5 yd . We are going to give a new layer of coating to the p
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Question 630350: At the park there is a pool shaped like a circle with radius 11yd. A ring-shaped path goes around the pool. Its width is 5 yd . We are going to give a new layer of coating to the path. If one gallon of coating can cover 8yd^2, how many gallons of coating do we need? Note that coating comes only by the gallon, so the number of gallons must be a whole number. (Use the value 3.14 for pi.) Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! At the park there is a pool shaped like a circle with radius 11yd.
A ring-shaped path goes around the pool.
Its width is 5 yd . We are going to give a new layer of coating to the path.
If one gallon of coating can cover 8yd^2, how many gallons of coating do we need?
Note that coating comes only by the gallon, so the number of gallons must be a whole number.
:
With a 5' path around the pool the overall radius (including the path)
11 + 5 = 16 ft
:
path area (pa) = Overall area - pool area
pa = (3.14*16^2) - (3.14*11^2)
:
pa = 803.84 - 379.94
pa = 423.9 sq/yds
:
Find the amt of coating needed: = 52.9875 ~ 53 gallons
:
:
Note that if you used a more accurate value for pi (like the one on your calc),
you would get slightly more than 53 gal, so if you were actually doing this,
54 gallons would be advisable.
