SOLUTION: Factor Completely. 3x^3-6x^2-12x+24 Thank You

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Question 630301: Factor Completely.
3x^3-6x^2-12x+24
Thank You
Found 2 solutions by dfrazzetto, ewatrrr:
Answer by dfrazzetto(283) About Me  (Show Source):
You can put this solution on YOUR website!

3x^3-6x^2-12x+24
Factor by grouping (special case):
3x^3 - 6x^2 - 12x + 24
3x^2(x-2) -12(x-2)
group like terms:
(3x^2 - 12)(x-2)
Factor out a 3:
3(x^2 - 4)(x-2)
Differences of squares: (a^2-b^2) = (a+b)(a-b)
3(x+2)(x-2)(x-2)

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

3x^3-6x^2-12x+24

3(x^3-2x^2-6x+12) = 0    x = 2 is one solution 

Using syntheitic division:

 2	1	-2	-12	24

 	 	2	  0	-24

 	1	0	-12	0

    x^2 - 12 = 0

     x^2 = 12

      x = ± 2sqrt%283%29

3x^3-6x^2-12x+24= 3%28x-2%29%2A%28x+-2sqrt%283%29%29%2A%28x%2B2sqrt%283%29%29