Question 630230: Find three consecutive odd numbers whose sum is 5 more than twice the next
consecutive number.
Answer by dfrazzetto(283) (Show Source):
You can put this solution on YOUR website! 2n+1, 2n+3, 2n+5, 2n+7
2n+1 + 2n + 3 + 2n+5 = 2(2n+7) + 5
6n + 9 = 4n + 14 + 5
2n = 10
n = 5
plugging back in to get the consecutive odd numbers:
11, 13, 15, 17
11 + 13 + 15 = 39 = 2(17) + 5 = 34 + 5 = 39
39 = 39
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