Question 630230:  Find three consecutive odd numbers whose sum is 5 more than twice the next  
    consecutive number. 
 
 Answer by dfrazzetto(283)      (Show Source): 
You can  put this solution on YOUR website! 2n+1, 2n+3, 2n+5, 2n+7
 
2n+1 + 2n + 3 + 2n+5 = 2(2n+7) + 5
 
6n + 9 = 4n + 14 + 5
 
2n = 10
 
n = 5
 
plugging back in to get the consecutive odd numbers:
 
11, 13, 15, 17
 
11 + 13 + 15 = 39 = 2(17) + 5 = 34 + 5 = 39
 
39 = 39
 
 
  | 
 
  
 
 |   
 
 |