SOLUTION: Suppose that the area of a circle is numerically equal to three times the perimeter of a square, and that the length of a radius of the circle is equal to the length of a side of t
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Question 630200: Suppose that the area of a circle is numerically equal to three times the perimeter of a square, and that the length of a radius of the circle is equal to the length of a side of the square. Find the length of a side of the square. Express your answer in terms of π.
You can put this solution on YOUR website! Suppose that the area of a circle is numerically equal to three times the perimeter of a square, and that the length of a radius of the circle is equal to the length of a side of the square. Find the length of a side of the square. Express your answer in terms of π.
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let x=side of square=radius of circle
Area of circle=π*radius^2=πx^2
3*perimeter of square=3*4x=12x
πx^2=12x
divide both sides by x
πx=12
x=12/π