SOLUTION: Wilma drove at an average speed of 55 mi/h from her home in City A to visit her sister in City B. She stayed in City B 20 hours, and on the trip back averaged 45 mi/h. She return
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Question 630177: Wilma drove at an average speed of 55 mi/h from her home in City A to visit her sister in City B. She stayed in City B 20 hours, and on the trip back averaged 45 mi/h. She returned home 41 hours after leaving. How many miles is City A from City B? Found 2 solutions by dfrazzetto, graphmatics:Answer by dfrazzetto(283) (Show Source):
You can put this solution on YOUR website! subtract the idle time in City B not moving:
41 - 20 = 21
d = vt
t = d/v
d/55 + d/45 = 21
LCM = 495
9d/495 + 11d/495 = 21
20d = 10395
d = 519.75 miles
CHeck:
519.75 / 55 + 519.75 / 45 = 9.45 hrs + 11.55 hrs = 21 hrs
You can put this solution on YOUR website! Let x be the distance from City A to City B. The time from City A to City B is x/55. The time from City B to City A is x/45. So x=519.75 miles
