SOLUTION: On my practice lesson, complex fractions. I am bit overwhelmed with questions with three or four terms in a fraction. Can anyone please help or explain how to solve? Find: (1

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: On my practice lesson, complex fractions. I am bit overwhelmed with questions with three or four terms in a fraction. Can anyone please help or explain how to solve? Find: (1      Log On


   

Question 629846: On my practice lesson, complex fractions.
I am bit overwhelmed with questions with three or four terms in a fraction.
Can anyone please help or explain how to solve?
Find:
(15ab-5a)/(16a^2-9) / 6b^3-2b^2/8ab+20a-6b-15
It's a division problem consisting of two fractions,
I understand I need to factor out. But the 8ab+20a-6b-15 is really throwing me off during the process, please help?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll help you factor 8ab+20a-6b-15. Hopefully that will get you going (if not, let me know)



8ab%2B20a-6b-15 Start with the given expression


%288ab%2B20a%29%2B%28-6b-15%29 Group the terms in two pairs


4a%282b%2B5%29-3%282b%2B5%29 Factor out the GCF 4a out of the first group. Factor out the GCF -3 out of the second group


%284a-3%29%282b%2B5%29 Since we have the common term 2b%2B5, we can combine like terms


So 8ab%2B20a-6b-15 factors to %284a-3%29%282b%2B5%29


In other words, 8ab%2B20a-6b-15=%284a-3%29%282b%2B5%29 for all values of 'a' and 'b'

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