SOLUTION: Becky and Sam are both taking History and attend independently. Becky attends 83.9% of the time and Sam attends 95.1% of the time.
-What is the probability that at least 1 will
Algebra ->
Probability-and-statistics
-> SOLUTION: Becky and Sam are both taking History and attend independently. Becky attends 83.9% of the time and Sam attends 95.1% of the time.
-What is the probability that at least 1 will
Log On
Question 629805: Becky and Sam are both taking History and attend independently. Becky attends 83.9% of the time and Sam attends 95.1% of the time.
-What is the probability that at least 1 will NOT be in class?
I believe that this is 1-(Probability of both in class). P=1-(.951*.839) or .20211
-What is the probability that NEITHER are in class on any given day?
I believe that this would be the complements multiplied: P= (.161*.049) or .007889
I think that I have worked these out correctly, but am not entirely sure.
