SOLUTION: a box contains 8 white balls, 4 black balls, and 9 red balls.
how many red balls must be added to the box so that the probability of drawing a red ball is 2/3 ?
how many black ba
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-> SOLUTION: a box contains 8 white balls, 4 black balls, and 9 red balls.
how many red balls must be added to the box so that the probability of drawing a red ball is 2/3 ?
how many black ba
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Question 629789: a box contains 8 white balls, 4 black balls, and 9 red balls.
how many red balls must be added to the box so that the probability of drawing a red ball is 2/3 ?
how many black balls must be added to the original box so that the probability of drawing a white ball is 1/3 ? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a box contains 8 white balls, 4 black balls, and 9 red balls.
total of 21 balls
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how many red balls must be added to the box so that the probability of drawing a red ball is 2/3 ?
Let the number added be "x".
Equation:
(9+x)/(21+x) = 2/3
3(9+x) = 2(21+x)
27 + 3x = 42+2x
x = 15
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how many black balls must be added to the original box so that the probability of drawing a white ball is 1/3 ?
Let the number be "x":
8/(21+x) = 1/3
21+x = 24
x = 3
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Cheers,
Stan H.
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