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px+1 = e5x
Take natural logs of both sides:
ln(px+1) = ln(e5x)
Use rules of logarithms:
(x+1)ln(p) = 5x
Distribute to remove parentheses:
x·ln(p) + ln(p) = 5x
Rearrange equation:
-5x + x·ln(p) = -ln(p)
Multiply through both sides by -1:
5x - x·ln(p) = ln(p)
Factor out x on the left
x[5-ln(p)] = ln(p)
Divide both sides by 5-ln(p)
x =
Edwin