Question 629569: The sum of twice the 1st, four times the 2nd plus the 3rd of the three consecutive even integers is equal to 96. find the integers Answer by ewatrrr(24785) (Show Source):
Hi,
three consecutive even integers ,,
The sum of twice the 1st, four times the 2nd plus the 3rd is equal to 96
Question states***
2x + 4(x+2) + (x+4) = 96
7x =84
x = 12 The three consecutive even integers are 12, 14, 16
