SOLUTION: Susan is 16 years older than her brother. 10 years later, she will be twice as old as her brother. Find the present ages of Susan and her brother.

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Susan is 16 years older than her brother. 10 years later, she will be twice as old as her brother. Find the present ages of Susan and her brother.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 629537: Susan is 16 years older than her brother. 10 years later, she will be twice as old as her brother. Find the present ages of Susan and her brother.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Susan is 16 years older than her brother's agehighlight%28x%29.
10 years later, she will be twice as old as her brother.
Question states*** 10 years from now...
(x+16) + 10 = 2(x+10)
6 = x, bother's age, Susan is 22
and ...10 yrs from now
32+=+2%2A16