SOLUTION: A gardener is fencing off a rectangular area with a fixed perimeter of 92 feet. What is the maximum area ?

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Question 629229: A gardener is fencing off a rectangular area with a fixed perimeter of 92 feet. What is the maximum area ?
Found 2 solutions by ewatrrr, solver91311:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
gardener is fencing off a rectangular area with a fixed perimeter of 92 feet.
P = 2%2AL+%2B+2%2AW+=+92ft or L++%2B+W+=+46ft
A Square with sides = 23ft would have the maximuum area = 529 ft^2

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!

The perimeter of a rectangle is given by:



Which can be rearranged to:



The area, given by length times width, can then be represented as a function of the width for a given perimeter thus:



This function is a quadratic that can be put into standard form thus:



The graph of such a quadratic is a parabola that is concave down (the lead coefficient is less than zero), meaning that the vertex represents a maximum. The coordinate of the vertex of this parabola is given by:



Therefore the width that gives the greatest area rectangle for any given perimeter is the perimeter divided by 4. The two widths are therefore half of the perimeter, hence the two lengths must also be half of the perimeter, and therefore the shape is a square.

Divide your given perimeter by 4 and then square the result.

John

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