SOLUTION: Scores on the Stanford-Binet Intelligence scale have a mean of 100 and a standard deviation of 16, and are presumed to be normally distributed. A person who scores a 132 on this s

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Question 629189: Scores on the Stanford-Binet Intelligence scale have a mean of 100 and a standard deviation of 16, and are presumed to be normally distributed. A person who scores a 132 on this scale has what percentile rank within the population? Show all work as to how this is obtained.
Answer by stanbon(75887) About Me  (Show Source):
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Scores on the Stanford-Binet Intelligence scale have a mean of 100 and a standard deviation of 16, and are presumed to be normally distributed. A person who scores a 132 on this scale has what percentile rank within the population? Show all work as to how this is obtained.
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z(132) = (132-100)/16 = 2
%ile rank: P(x < 2) = 97.72
Rounded up the %ile rank = 98%ile
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Cheers,
Stan H.