Question 629167: ONE NUMBER EXCEEDS ANOTHER BY 5. TWO TIMES THE SMALLER NUMBER DIMINISHED BY THE LARGER NUMBER EQUALS 9. FIND THE TWO NUMBERS? Answer by 303795(602) (Show Source):
You can put this solution on YOUR website! Let the smaller number be x. This means that the second number is 5 larger than x.
Number 1 = x
Number 2 = x + 5
2 times the smaller number is 2x.
Using this information we then get the equation
2x - (x + 5) = 9
Remove the bracket by multiplying the contents by minus
2x - x - 5 = 9
x - 5 = 9 Add 5 to each side to get
x = 9 + 5 = 14
So the second number must be 19.
Check 2 x 14 - 19 = 9
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