SOLUTION: area of a rectangle is 40 cm squared and one of its sides is 8 cm long.what is the width and perimeter of the rectangle?
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Question 629137: area of a rectangle is 40 cm squared and one of its sides is 8 cm long.what is the width and perimeter of the rectangle? Answer by 303795(602) (Show Source):
You can put this solution on YOUR website! The area of a rectangle is found by multiplying the length by the width.
ie A = l x w
given that the area is 40 square cm and one side is 8cm (I'll assume that it is the length) the formula becomes
40 = 8 x w
Divide each side by 8 then
40/8 = (8 x w)/8
5 = w
So the width must be 5 cm.
Perimeter = 2 x (l + w)
=2 x (8 + 5)
=2 x 13
=26 cm
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