SOLUTION: need help..The altitude in feet of a projectile t seconds after launch is given by the function s(t)=-16t^2+32t+3. How long after launch will it take for the projectile to reach i
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-> SOLUTION: need help..The altitude in feet of a projectile t seconds after launch is given by the function s(t)=-16t^2+32t+3. How long after launch will it take for the projectile to reach i
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Question 62899: need help..The altitude in feet of a projectile t seconds after launch is given by the function s(t)=-16t^2+32t+3. How long after launch will it take for the projectile to reach its maximum height? What is the maximum height?
thanks for your help Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! s(t)=-16t^2+32t+3. How long after launch will it take for the projectile to reach its maximum height? What is the maximum height?
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You have a quadratic with a=-16, b=32
Since a is negative, the function has a maximum at x=-b/(2a)
=-32/(-32)=1 second.
The height at that time is:
f(1)=-16+32+3=19 ft.
Cheers,
Stan H.
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