SOLUTION: Show that the equations 8a - 10b = 1/3 and 20a - 25b= 5/6 have many solutions.
Is it......
A) (20,50)
B) (-3,-3)
C) (3,2)
D) infinitely many
E) (5,4)
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-> SOLUTION: Show that the equations 8a - 10b = 1/3 and 20a - 25b= 5/6 have many solutions.
Is it......
A) (20,50)
B) (-3,-3)
C) (3,2)
D) infinitely many
E) (5,4)
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Question 628967: Show that the equations 8a - 10b = 1/3 and 20a - 25b= 5/6 have many solutions.
Is it......
A) (20,50)
B) (-3,-3)
C) (3,2)
D) infinitely many
E) (5,4) Answer by solver91311(24713) (Show Source):
A linear system has either zero, one, or infinitely many solutions. I.e. your system cannot have "many solutions" unless it has infinite solutions.
Multiply both equations by the reciprocal of the constant term (i.e. the fraction in the RHS). You will find that they are both the same equation and therefore the graphs of the two lines are coincident having and infinite number of points of intersection.
John
My calculator said it, I believe it, that settles it
