SOLUTION: Having a problem figuring out this algebra. Any help will be appreciated thanks (4+8i)(4-8i)

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Question 628948: Having a problem figuring out this algebra. Any help will be appreciated thanks
(4+8i)(4-8i)

Found 2 solutions by stanbon, lwsshak3:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(4+8i)(4-8i)
----
4(4-8i)+8i(4-8i)
---
= 16 - 32i + 32i + 64
---
= 80
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Cheers,
Stan H.
============

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Having a problem figuring out this algebra. Any help will be appreciated thanks
(4+8i)(4-8i)
**
You should recognize this the factored form of the difference of two squares which go like this:
(a+b)(a-b)=a^2-b^2
..
(4+8i)(4-8i)
=4^2-(8i)^2
=16-64i^2
i^2=-1
=16+64
=80