SOLUTION: tan^2x + cot^2x = 1 - 2sin^2x + 2sin^4x / sin^2x - sin^4x

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Question 628942: tan^2x + cot^2x = 1 - 2sin^2x + 2sin^4x / sin^2x - sin^4x
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
tan^2x + cot^2x = 1 - 2sin^2x + 2sin^4x / sin^2x - sin^4x
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