SOLUTION: I'm trying to find the answer to this question "A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 300 feet of fenci

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Question 628819: I'm trying to find the answer to this question "A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 300 feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed?"
Found 2 solutions by richwmiller, Alan3354:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
the largest area will be a square.
so three equal sides =300 feet
100 ft a side
100*100=10000 sq ft

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
"A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 300 feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed?"
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Area = L*W
L + 2W = 300 --> L = 300 - 2W
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Area = W*(300 - 2W) = 300W - 2W^2
Area = f(W) = -2W^2 + 300W
That's a parabola whose vertex is the maximum
The axis of symmetry is W = -b/2a = -300/(-4)
W = 75 ft for max area
L = 150 ft
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Area = 75*150 = 11250 sq ft