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the question is (sec y/(sec y - cos y)) = cosec^2 y
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the question is (sec y/(sec y - cos y)) = cosec^2 y
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Question 628762: hello there...i am having a problem with this question...can you help me solve it???
the question is (sec y/(sec y - cos y)) = cosec^2 y Answer by Tatiana_Stebko(1539) (Show Source):