SOLUTION: hello there...i am having a problem with this question...can you help me solve it??? the question is (sec y/(sec y - cos y)) = cosec^2 y

Algebra ->  Trigonometry-basics -> SOLUTION: hello there...i am having a problem with this question...can you help me solve it??? the question is (sec y/(sec y - cos y)) = cosec^2 y       Log On


   



Question 628762: hello there...i am having a problem with this question...can you help me solve it???
the question is (sec y/(sec y - cos y)) = cosec^2 y

Answer by Tatiana_Stebko(1539) About Me  (Show Source):