SOLUTION: the sum of four consecutive odd integers is 56 find the first
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Question 628741
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the sum of four consecutive odd integers is 56 find the first
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Let the first odd integer be 2n+1. The next three consecutive odd integers are 2n+3, 2n+5 and 2n+7. So 2n+1+2n+3+2n+5+2n+7=56. 8n+16=56. 8n=40. n=5. So the first odd integer is 2*5+1. 11.
