SOLUTION: log20x-log2=0.6180

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Question 62868: log20x-log2=0.6180
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
I am assuming that there are no written bases, thus these are common logs with an understood base of 10.
log20x-log2=0.6180
log20x/2=0.6180
log10x=0.6180
10^0.6180=10x
10^0.6180/10=10x/10
10^(0.6180-1)=x
10^(-.382)=x
.4149540426=x Round it off to what ever you're told to.
Check by storing this for x in your graphing calculator and typing in the problem to see if the answer is valid and not extraneous.
It's valid.
highlight%28x=.4149540426%29
Happy Calculating!!!