SOLUTION: Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 k

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Question 628629: Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. Find the distance between P and Q.




Need answer with solution urgently.. Thanks a million..

Found 2 solutions by richwmiller, MathTherapy:
Answer by richwmiller(17219) About Me  (Show Source):
Answer by MathTherapy(10551) About Me  (Show Source):
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Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. Find the distance between P and Q.
Need answer with solution urgently.. Thanks a million..

Let distance traveled by faster train be D
Then distance traveled by slower train = D - 100
Time taken by faster train to travel to meeting point = time taken by slower train to travel to the meeting point, OR
D%2F50+=+%28D+-+100%29%2F40

50(D – 100) = 40D ------ Cross-multiplying

50D – 5,000 = 40D

50D - 40D = 5,000

10D = 5,000
D, or distance traveled by faster train = 5000%2F10, or 500 km

Distance traveled by slower train = 500 – 100, or 400 km

Therefore, distance between P and Q = 500 + 400, or highlight_green%28900%29 km

You can do the check, I'm sure!!

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