Question 628558: The smaller of two numbers is 4 less than the larger. If the sum of their squares is 58, find the numbers. Answer by ewatrrr(24785) (Show Source):
Hi,
The smaller of two numbers is 4 less than the larger.
Question states*** sum of their squares is 58
x^2 + (x-4)^2 = 58
x^2 + x^2 - 8x + 16 = 58
2x^2 -8x -42 = 0
x^2 - 4x - 21 = 0
solve by factoring:
