SOLUTION: Hi, I need help with this logarithm:
log base 2 of (x) + log base 2 of (x+2)=log base 2 of (x+6)
I have attempted this equation but I keep coming to the solution of x=(x+6)/(x+
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-> SOLUTION: Hi, I need help with this logarithm:
log base 2 of (x) + log base 2 of (x+2)=log base 2 of (x+6)
I have attempted this equation but I keep coming to the solution of x=(x+6)/(x+
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Question 628409: Hi, I need help with this logarithm:
log base 2 of (x) + log base 2 of (x+2)=log base 2 of (x+6)
I have attempted this equation but I keep coming to the solution of x=(x+6)/(x+2) and I don't know how to solve for x.
Please and thank you :) Answer by John10(297) (Show Source):
You can put this solution on YOUR website! log base 2 of (x) + log base 2 of (x+2)=log base 2 of (x+6)
So we will have:
log base 2 of [x(x+2)] = log base 2 of (x + 6)
x(x +2) = x + 6
x^2 + 2x = x + 6
x^2 + x - 6= 0
(x +3)(x - 2) = 0
x = -3 or x = 2
We can NOT choose x = -3 because property of log x which x can not be negative.
Thus the ONLY solution is x = 2.
Hope it helps:)
John10
