SOLUTION: Please help me solve this problem: what is the square root of n+9 (under square root sign) +3=n (not under the square root sign Thank you

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help me solve this problem: what is the square root of n+9 (under square root sign) +3=n (not under the square root sign Thank you      Log On


   

Question 62825: Please help me solve this problem: what is the square root of n+9 (under square root sign) +3=n (not under the square root sign
Thank you
Answer by 303795(602) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28n%2B9%29%2B3=n Subtract 3 from each side
sqrt%28n%2B9%29%2B3-3=n+-+3
sqrt%28n%2B9%29=n+-+3 Square each side
n%2B9=%28n+-+3%29%5E2
n%2B9=n%5E2+-+6n+%2B+9 Subtract 9 from each side
n%2B9-9=n%5E2+-+6n+%2B+9-9
n=n%5E2+-+6n+ Subtract n from each side
n-n=n%5E2+-+6n+-n
0=n%5E2+-+7n
0=n%28n-7%29
ie n = 7 or n = 0