SOLUTION: What is wrong with solving 2x^5 – 8x^3 + 5x^2 – 3x = 0 by dividing both sides by x?
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Question 628227
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What is wrong with solving 2x^5 – 8x^3 + 5x^2 – 3x = 0 by dividing both sides by x?
Answer by
richwmiller(17219)
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x=0 is one solution
There are four more. Two real and two complex(imaginary)
x *(2x^4-8x^2+5 x-3) = 0