SOLUTION: Write the expression as a single logarithm with a coefficient of 1. Assume all variable expressions represent positive real numbers. logb(3x) + logb(y + 4) + logb(y + 2) &#8722

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Write the expression as a single logarithm with a coefficient of 1. Assume all variable expressions represent positive real numbers. logb(3x) + logb(y + 4) + logb(y + 2) &#8722      Log On


   

Question 628158: Write the expression as a single logarithm with a coefficient of 1. Assume all variable expressions represent positive real numbers.

logb(3x) + logb(y + 4) + logb(y + 2) − logb(y2 + 6y + 8)
= ?
Answer by lwsshak3(11628) About Me  (Show Source):
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Write the expression as a single logarithm with a coefficient of 1. Assume all variable expressions represent positive real numbers.
logb(3x) + logb(y + 4) + logb(y + 2) − logb(y^2 + 6y + 8)
logb(y^2 + 6y + 8)=log[(y+4)(y+2)]
logb[(3x(y+4)(y+2))/(y+4)(y+2)]
(y+4)(y+2) cancels out, leaving:
logb(3x)