Question 628019: Last fall, a sample of n = 36 freshmen was selected to participate in a new 4-hour training program designed to improve study skills. To evaluate the effectiveness of the new program, the sample was compared with the rest of the freshmen class. All freshmen must take the same English Language Skills course, and the mean score on the final exam for the entire freshmen class was u = 74.00. The students in the new program had a mean score of M = 86.40 with a standard deviation of s = 18.00. Test is the study skills training program produced a significant difference in scores usin an alpha = .01.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Last fall, a sample of n = 36 freshmen was selected to participate in a new 4-hour training program designed to improve study skills. To evaluate the effectiveness of the new program, the sample was compared with the rest of the freshmen class. All freshmen must take the same English Language Skills course, and the mean score on the final exam for the entire freshmen class was u = 74.00. The students in the new program had a mean score of M = 86.40 with a standard deviation of s = 18.00. Test is the study skills training program produced a significant difference in scores usin an alpha = .01.
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Ho: u = 74
Ha: u # 74
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z(86.40) = (86.40-74)/[18/sqrt(36)] = 12.4/3 = 4.1
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p-score = 2*P(z > 4.1) = 0.000041337
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Conclusion: Since the p-score is less than 1%, reject Ho.
The study skills training program did produce a significant difference.
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Cheers,
Stan H.
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