SOLUTION: what is the foci of this ellipse. x^2/64 + y^2 =1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: what is the foci of this ellipse. x^2/64 + y^2 =1      Log On


   



Question 627989: what is the foci of this ellipse. x^2/64 + y^2 =1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
what is the foci of this ellipse.
x^2/64 + y^2 =1
This is an equation of an ellipse with horizontal major axis
center: (0,0)
a^2=64
a=√64=8
b^2=1
b=1
c^2=a^2-b^2=64-1=63
c=√63≈7.9
foci: (0±c,0)=(0±7.9,0)=(-7.9,0) and (7.9,0)