You can put this solution on YOUR website! find the polynomial f(X) of degree three that has zeroes at 1,2 and 4 such that f(0)= -16.
---------
f(x)=a(x-1)(x-2)(x-4)
f(0)=a(-1)(-2)(-4)=-8a
-8a=-16
a=2
--------
EQUATION:
f(x)=2(x-1)(x-2)(x-4)
Cheers,
Stan H.