Question 62792: For the functions f(x) = 4x + 7 and g(x) = -9x + 11,
find f(g(0)).
For the functions f(x) = 3x2 - 7
and g(x) = -3x2 + 4,
find f(g(2)). (Do NOT put commas in large numbers.)
For the functions f(x) = 3x2 - 7
and g(x) = -3x2 + 8,
find g(f((-4)). (Do NOT put commas in large numbers.)
For the functions f(x) = 3x2 - 8
and g(x) = -7x2 + 5,
find g(f((-4)). (Do NOT put commas in large numbers.)
For the functions f(x) = 3x + 6 and g(x) = -10x + 3,
find g(f((4)).
Answer by funmath(2933)   (Show Source):
You can put this solution on YOUR website! For the functions f(x) = 4x + 7 and g(x) = -9x + 11,
find f(g(0)).
f(-9(0)+11)=f(11)=4(11)+7=44+7=51
:
For the functions f(x) = 3x^2 - 7
and g(x) = -3x^2 + 4,
find f(g(2)). (Do NOT put commas in large numbers.)
f(-3(2)^2+4)=f(-3(4)+4)=f(-12+4)=f(-8)=3(-8)^2-7=3(64)-7=192-7=185
:
For the functions f(x) = 3x^2 - 7
and g(x) = -3x^2 + 8,
find g(f((-4)). (Do NOT put commas in large numbers.)
g(3(-4)^2-7)=g(3(16)-7)=g(48-7)=g(41)=-3(41)^2+8=-3(1681)+8=-5043+8=-5035
:
For the functions f(x) = 3x^2 - 8
and g(x) = -7x^2 + 5,
find g(f((-4)). (Do NOT put commas in large numbers.)
g(3(-4)^2-8)=g(3(16)-8)=g(48-8)=g(40)=-7(40)^2+5=-7(1600)+5=-11200+5=-11195
:
For the functions f(x) = 3x + 6 and g(x) = -10x + 3,
find g(f((4)).
g(3(4)+6)=g(12+6)=g(18)=-10(18)+3=-180+3=-177
Happy Calculating!!!
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