SOLUTION: I am still stuck with this question so will one of you please help me with it. A fisherman recorded the number of fish he took from each trap. The average number of fish per trap

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Question 627910: I am still stuck with this question so will one of you please help me with it.
A fisherman recorded the number of fish he took from each trap. The average number of fish per trap was 230 with a standard deviation of 22. What number of fish per trap would he expect in the interval symmetrical about the mean where 80% of the numbers would be found.
Thank you
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

MEAN = 230 with a standard deviation of 22

 .10  ⇒ Z = -1.2816 = (X-230)/22  OR X = 22%2A-1.2816+%2B+230+=+202

 .90  ⇒ Z = 1.2816 = (X-230)/22  OR X = 22%2A1.2816+%2B+230+=+258

What number of fish per trap would he expect in the interval symmetrical about the mean 

where 80% of the numbers would be found.  202 to 258 fish per trap