SOLUTION: I need some help on how to find the solution to this problem. find three consecutive integers for which four times the largest is 86 more than the sum of the first two.

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Question 627360: I need some help on how to find the solution to this problem. find three consecutive integers for which four times the largest is 86 more than the sum of the first two.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I think something is missing or mistaken.
As posted, the problem has no solution.
The problem should start with "find three consecutive EVEN integers".
Then, the solution would be 36, 38 and 40.
A step-by-step solution could be as follows.
Let n be the largest integer.
The three consecutive EVEN integers would be
n-4 , n-2 , and n .
Four times the largest would be 4n,
and we know that 4n equals 86 more than the sum of the first two, so
4n=%28n-4%29%2B%28n-2%29%2B86.
The equation above can be solved as follows.
4n=%28n-4%29%2B%28n-2%29%2B86 --> 4n=n-4%2Bn-2%2B86 --> 4n=2n%2B80 --> 2n=80 --> highlight%28n=40%29